Solve the 3rd order polynomial equation shown below.
1.5x3 - 7x2 - 5.8x + 5 = 0
/* Root of 3rd order polynomial */ 1.5*x^3 - 7*x^2 - 5.8*x + 5 = 0
Explanation
- ^ represents a power.
- The iterative method is necessary to solve non-linear equations, and initial estimate values are specified for the calculation.
- If you do not specify an initial estimate value in the RESET statement, then the default value (0) will automatically be set.
- This cubic equation contains 3 roots and if this is executed as is, only one of them will be solved.
Enter equations and click on the [Solve] button.
/* Root of 3rd order polynomial */ eq: 1.5*x^3 - 7*x^2 - 5.8*x + 5 = 0 RESET x#10 BY eq
Explanation
- To solve the other two roots, initial estimate values must be given by adding the RESET statement as shown above. # means an initial value, and in the BY clause, the equation that verifies the convergence is specified.
- eq is the label attached to the equation.
Enter equations and click on the [Solve] button.